We have seen in the previous section that a curve like y=1+2x+3{\displaystyle y = 1 + \frac{2}{x+3}} has asymptotes x=−3x=-3 and y=1.y=1.

Now let us look at a curve described by an improper fraction y=6x−13x+2{\displaystyle y = \frac{6x-1}{3x+2}}. The horizontal asymptote x=−23x=-\frac{2}{3} can be deduced easily, but the vertical asymptote is harder to figure out as both 6x−16x-1 and 3x+23x+2 tend to infinity as x→∞.x \to \infty.

We will tackle this, as well as more complicated improper fractions like y=2x2+7x−3x+3{\displaystyle y = \frac{2x^2+7x-3}{x+3}}, by long division.

Examples

2{2}
3x+2{3x+2}
){)}
6x{6x}
−{-}
1{1}
−({-(}
6x{6x}
−{-}
4){4)}
3{3}
2x{2x}
+{+}
2{2}
x+3{x+3}
){)}
2x2{2x^2}
+{+}
7x{7x}
−{-}
3{3}
−({-(}
2x2{2x^2}
+{+}
6x){6x)}
x{x}
−{-}
3{3}
−({-(}
x{x}
+{+}
3){3)}
−{-}
6{6}

Asymptotes

Since y=6x−13x+2=2+33x+2\displaystyle {y = \frac{6x-1}{3x+2}} \allowbreak {= 2 + \frac{3}{3x+2}}, we can see clearly that the horizontal asymptote is y=2y=2.

We will tackle the result of the second example y=2x2+7x−3x+3=2x+2−6x+3\displaystyle {y = \frac{2x^2+7x-3}{x+3}} \allowbreak {= 2x+2 - \frac{6}{x+3}} in section 3.1.4.

In the next section, however, we will first look at more examples of the first type.

Next: Rectangular hyperbola >>